go - Does calling a function break recover()? -

i using library recover()s panics, , using code simplifies following:

func main() {     defer rec()     panic("x") }  func rec() {     rec2() }  func rec2() {     fmt.printf("recovered: %v\n", recover()) } 

the output of is:

recovered: <nil> panic: x ... more panic output ... 

notably, recover() returns nil instead of error. intended behavior?

recover must called directly deferred function.

from language spec:

the return value of recover nil if of following conditions holds:

• panic's argument nil;
• the goroutine not panicking;
• recover not called directly deferred function.