go - Does calling a function break recover()? -

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i using library recover()s panics, , using code simplifies following:

func main() {     defer rec()     panic("x") }  func rec() {     rec2() }  func rec2() {     fmt.printf("recovered: %v\n", recover()) }

the output of is:

recovered: <nil> panic: x ... more panic output ...

notably, recover() returns nil instead of error. intended behavior?

recover must called directly deferred function.

from language spec:

the return value of recover nil if of following conditions holds:

  • panic's argument nil;
  • the goroutine not panicking;
  • recover not called directly deferred function.

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