vb.net - Value of type '1-dimensional array of String' cannot be converted to '1-dimensional array of Integer' because 'String' is not derived from 'Integer' -


i getting error while trying use linear search name entered user array. here when declare array , input.

public const size_array = 9  public sub cmdstart_click(sender object, e eventargs) handles cmdstart.click  dim myarray(size_array) string dim index integer public sub cmdstart_click(sender object, e eventargs) handles cmdstart.click     dim count integer = 0      me.index = 0 size_array         myarray(index) = inputbox("enter name, enter name")         count = count + 1     next  if count = 10         lblinstructions.visible = false         cmdstart.visible = false         lblinstructions2.visible = true         txtsearch.visible = true         lbloutput.visible = true         cmdsearch.visible = true     end if end sub 

here use linear search.

public sub cmdsearch_click(sender object, e eventargs) handles cmdsearch.click     dim found boolean     dim name string      name = txtsearch.text      found = linearsearch(myarray, val(name))      if found         lbloutput.text = name & " found @ cell " & index     else         lbloutput.text = name & " not found"     end if  end sub 

and here linear search function

public function linearsearch(byval list() integer, byval searchvalue integer) boolean     dim found boolean = false     dim index integer     while found = false , index <= ubound(list)         if list(index) = searchvalue             found = true         else             index += 1         end if     end while     return found end function 

myarray string array, method linearsearch expects 2 arguments: integer array , integer. assume require array search of type string, , search value of type string

my vb.net rusty, here untested code linear search.

public function linearsearch(byval list() string, byval searchvalue string) boolean         each item string in list             if item = searchvalue                  return true             end if          next         return false end function   

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