java - how to use the count() function to get an element with a specific number of inner tags -

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i using java , selenium write test. in dom, have 2 svg tags. 1 of them has more 2 inner path tags. need svg used:

wait.until(expectedconditions.presenceofelementlocated(by.xpath(                         "//*[local-name() = 'svg' , count(.//path)>'2']")));

or 

 wait.until(expectedconditions.presenceofelementlocated(by.xpath(                             "//*[local-name() = 'svg'] [count(.//path)>'2']")));

but doesn't work. need know what's wrong please offer other ways around. thanks.

by way worked for:

//*[local-name() = 'svg' , count(.//*[local-name() = 'path' ])>'1']

or 

//*[local-name() = 'svg'][ count(.//*[local-name() = 'path' ])>'1']

the problem trying find .//path svg element. far know, cannot because svg elements different namespace. mentioned in question, can fix using [local-name() = 'path' ]. workaround using jsexecutor execute method document.evaluate() can specify namespace of svg. see example @ post.


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