python - Initializing a command that's failing with popen -

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i trying run "repoinitcmd" using popen below , running following error..can provide inputs on wrong?

import subprocess branch_name='ab_mr2' repoinitcmd =  'repo init -u git://git.company.com/platform/manifest.git -b ' + branch_name proc = subprocess.popen([repoinitcmd], stderr=subprocess.pipe) out, error = proc.communicate()

error:-

  file "test.py", line 4, in <module>     proc = subprocess.popen([repoinitcmd], stderr=subprocess.pipe)   file "/usr/lib/python2.7/subprocess.py", line 679, in __init__     errread, errwrite)   file "/usr/lib/python2.7/subprocess.py", line 1249, in _execute_child     raise child_exception oserror: [errno 2] no such file or directory

by default, popen expects command line passed list. in particular, actual command run (in case 'repo') should first item of list. rather writing commands strings , using split or shlex pass them popen lists, prefer manage command lines lists start, makes easier build command line in code. so, in case might have written this:

repoinitcmd = ['repo', 'init', '-u', 'git://git.company.com/platform/manifest.git'] repoinitcmd.extend(['-b', branch_name]) proc = subprocess.popen(repoinitcmd, stderr=subprocess.pipe)

note, if want or need pass command line single string (perhaps take advantage of shell features), can enable shell mode if don't mind additional overhead of running shell process:

proc  = subprocess.popen(repoinitcmd, shell=true, stderr=subprocess.pipe)

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