Reading an Rank 2 array in FORTRAN 95 -

i want read array text file looks this

1   88  90  94  102 111 122 134 2   75  77  80   86  94 103 113 3   80  83  85   94 100 111 121  4   68  71  76   85  96 110 125 5   77  84  91   98 105 112 119 6   81  85  90   96 102 109 120 

(above data 6 8 matrix, evenly spaced, might not show correctly

my code

program cool implicit none integer:: ok(6,8),k,i open(unit = 1, file = "a.txt") read(1,*) ok write(*,*) ok print*,ok_1(4,3) end program cool 

the issue having ok(4,3) not correspond 71 ( 4th row down ,3rd column)

i have tried read file such read(unit =1,10) ok 10 format ( 8(i4))

! have tried variants of this

what ever way try, calling ok(i,j) not correspond value need

i need find row averages , column averages out column 1 included. simple loops long can correct values, can not

edit:: have tried hard code array in program ok = reshape((/1,88,90,94,102,111,122,134,& 2,75,77,80,86 ,94 ,103,113,& 3,80,83,85,94 ,100,111,121,& 4,68,71,76,85 ,96 ,110,125,& 5,77,84,91,98 ,105,112,119,& 6,81,85,90,96 ,102,109,120/),(/6,8/)) not seem make correspond aswell ok(4,4) returns 100 not 76

fortran stores arrays in memory in column-major order, element ok(1,1) followed element ok(2,1), ok(3,1), ... , on. convenient statement

read(1,*) ok 

reads numbers array in order. using reshape on same list of elements results in same array.

perhaps thought array stored in row-major order, ok(1,1), ok(1,2), ok(1,3), ... ?

you either read file line line, like

do ix = 1, 6    read(1,*) ok(ix,:) end 

or read file in 1 gulp 8*6 temporary array , transpose it. or re-order elements in file.